Convert to binary from base-10

This a problem set for you to work through

This is a problem set. Some of these are easy, others are far more difficult. The purpose of these problems sets are:

1. to build your skill applying computational thinking to a problem
2. to assess your knowledge and skills of different programming practices

What is this problem set trying to do

The actual solution to this problem is fairly straight-forward, but imagining how to solve the problem is tricky. As a side note, you must understand how to convert base 10 to base 2.

The Problem

Ask the user to enter a number in base 10. Then convert the number the user entered into binary. Extra points if you ensure the binary always has 8 digits

Unit Tests

• User Input: 1
• Expected output: 1

• User Input: 4
• Expected output: 100

• User Input: 8
• Expected output: 1000

How you will be assessed

Your solution will be graded using the following axis:

Scope

• To what extent does your code implement the features required by our specification?
• To what extent is there evidence of effort?

Correctness

• To what extent did your code meet specifications?
• To what extent did your code meet unit tests?
• To what extent is your code free of bugs?

Design

• To what extent is your code written well (i.e. clearly, efficiently, elegantly, and/or logically)?
• To what extent is your code eliminating repetition?
• To what extent is your code using functions appropriately?

Style

• To what extent is your code readable?
• To what extent is your code commented?
• To what extent are your variables well named?
• To what extent do you adhere to style guide?

A possible solution

Click the expand link to see one possible solution, but NOT before you have tried and failed!

#first off, we need something to convert (duh), so we are asking the user to feed a base 10 number to the program by using the input function
number = int(input("What base 10 nr would you like to convert to binary? Please enter it below \n > "))

#setting an empty string. This is where the binary equivalent of the above input will be
binary = ""

#getting to the mathy part. This system was inspired by the tutorial over from https://www.electronics-tutorials.ws/binary/bin_2.html, where it tells you to just keep diving the number by 2 until you get it down to 0. 
while number != 0:
    #checking if the number has a remainder 
    if number%2 == 1:
        #if the number DOES have a remainder, we need to a 1 in our binary string (cause that's the remainder)
        binary += "1"
        # rounding the number down because decimals would mess this up
        number = int(number/2)

    # checking if the number does not have a remainder
    elif number %2 == 0:
        #if the number DOESN'T have a remainder, we need to a 0 in our binary string (cause there's no remainder)
        binary += "0"
        # rounding the number down because decimals would mess this up
        number = int(number/2)


#this part was grabbed over from https://www.educative.io/edpresso/how-do-you-reverse-a-string-in-python. These are the 2nd and 3rd from the last block of code on the page
#this is needed because according to the tutorial, the result of the first time we divide the number (either a 0 or 1) is the "Least Significant Bit" and the result of the last time we divied is the "Most Significant Bit"
#we gotta swap it because it's backwards right now. It's from LSB to MSB right now, and it needs to be from MSB to LSB
reversed =''.join(reversed(binary)) 
#printing the result 
print(reversed)

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