Tic tac toe: Difference between revisions

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Click the expand link to see one possible solution, but NOT before you have tried and failed!  
Click the expand link to see one possible solution in Python, but NOT before you have tried and failed!  
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Click the expand link to see one possible solution in Javascript, but NOT before you have tried and failed!
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[[File:Javascript tictactoe one answer.zip]]
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[[Category:problem set]]
[[Category:problem set]]

Revision as of 10:08, 1 April 2019

This a problem set for you to work through [1]

This is a problem set. Some of these are easy, others are far more difficult. The purpose of these problems sets are:

  1. to build your skill applying computational thinking to a problem
  2. to assess your knowledge and skills of different programming practices


What is this problem set trying to do[edit]

This problem set is testing your computational thinking, your skill and understanding of lists, and your skill and understanding of loops

The Problem[edit]

Your program must do three things:

  1. it must allow a human to play against a computer a game of tic tac toe
    1. your program must have win and lose conditions
  2. it must draw a tic tac to board, updated with x's and O's as the computer and human play.
  3. It must follow the rules of tic tac toe


Hacker edition[edit]

In the hacker version:

  • Your program should be good at playing tic tac toe

Python Version[edit]

import random

# initialization stuff here: 

board = [1,2,3,4,5,6,7,8,9]
computerSpaces = []
humanSpaces =[1]
game = 0

def drawPieces(position):
    if position in humanSpaces:
        return "X"
    elif position in computerSpaces:
        return "O"
    else:
        return position   



# this function draws the board
def drawBoard():
    print("")
    print("")
    print(" ",drawPieces(1),"  |   (2)    | (3) ")
    print("     |          |     ")
    print("----------------------")
    print(" (4) |   (5)    | (6) ")
    print("     |          |     ")
    print("----------------------")
    print(" (7) |   (8)    | (9) ")
    print("     |          |     ")
    
    return

# this function manages player moves
def playerMove(move):
    return

# this function manages computer moves
def computerMove(computerMove):
    return

while True:
    print(drawBoard())
    move=input("Please choose a move (99 to quit): ")
    if move == "99":
        break
    elif str(move) in computerSpaces or str(move) in humanSpaces:
        print("this is a invalid move")
    else:
        humanSpaces.append(move)
        print(humanSpaces)
   # playerMove(move)

Javascript Version[edit]

File:Javascript tictactoe.zip


How you will be assessed[edit]

Your solution will be graded using the following axis:


Scope

  • To what extent does your code implement the features required by our specification?
  • To what extent is there evidence of effort?

Correctness

  • To what extent did your code meet specifications?
  • To what extent did your code meet unit tests?
  • To what extent is your code free of bugs?

Design

  • To what extent is your code written well (i.e. clearly, efficiently, elegantly, and/or logically)?
  • To what extent is your code eliminating repetition?
  • To what extent is your code using functions appropriately?

Style

  • To what extent is your code readable?
  • To what extent is your code commented?
  • To what extent are your variables well named?
  • To what extent do you adhere to style guide?

References[edit]

A possible solution[edit]

Click the expand link to see one possible solution in Python, but NOT before you have tried and failed!

import random

# initialization stuff here: 

board = [1,2,3,4,5,6,7,8,9]
computerSpaces = []
humanSpaces =[]
game = 0

# this function draws pieces on the board. 
def drawPieces(position):
    if position in humanSpaces:
        return "X"
    elif position in computerSpaces:
        return "O"
    else:
        return position   


# this function manages player moves
def playerMove(move):
    humanSpaces.append(move)
    humanSpaces.sort()
    board.remove(int(move))
    return

# this function manages computer moves
def computerMove():
    # we choose a possible move from any moves left in the list board
    move=random.choice(board)
    # we append the move we just made into a list
    computerSpaces.append(str(move))
    # we sort the list because our win conditions are in a certain order. 1,2,3 is a win, but 3,2,1 isn't. 
    # sorting is a bit of a hack (there might be a better way to test for membership in a list iregardless of order)
    computerSpaces.sort()
    # finally, we remove the place from our list keeping track of the places. 
    board.remove(move)
    return

# this function draws the board
def drawBoard():
    print("")
    print("")
    print(" ",drawPieces('1'),"  |   ",drawPieces('2'),"    | ",drawPieces('3'), "  ")
    print("      |          |     ")
    print("----------------------")
    print(" ",drawPieces('4'),"  |   ",drawPieces('5'),"    | ",drawPieces('6'), "  ")
    print("      |          |     ")
    print("----------------------")
    print(" ",drawPieces('7'),"  |   ",drawPieces('8'),"    | ",drawPieces('9'), "  ")
    print("      |          |     ")
    return

# this functions looks for win win conditions
def winConditions():
    winConditions = [['1','2','3'],['4','5','6'],['7','8','9'],['1','5','9'],['3','5','7'],['1','4','7'],['2','5','8'],['3','6','9']]
    if any(humanSpaces) in winConditions:
        print("human won")
        raise SystemExit
    elif any(computerSpaces) in winConditions:
        print("commputer won")
        raise SystemExit
    return


# main game loop
while True:
    print(board)
    print(drawBoard())
    move=input("Please choose a move (99 to quit): ")
    if move == "99":
        break
    elif str(move) in computerSpaces or str(move) in humanSpaces:
        print("this is a invalid move")
    else:
        playerMove(move)
        computerMove()
        winConditions()
        print(humanSpaces)
        print(computerSpaces)
        # playerMove(move)


Click the expand link to see one possible solution in Javascript, but NOT before you have tried and failed!