Leaderboard: Difference between revisions

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not yet!
#This awesome code was written by Filip from grade 11
#Hope you can learn something from this
#Date added 10.04.19
 
user1 = [123, 4, 13, 6, [[1,1],[2,5],[3,1],[4,2]]]
user2 = [842, 7, 20, 7, [[1,8],[2,4],[3,9],[4,20]]]
user3 = [945, 9, 12, 25, [[1,3],[2,1],[3,4],[4,34]]]
 
def find_total_points(user):
    for i in range (0, len(user[4])):
        quiz_points = 0
        quiz_points = quiz_points + user[4][i][-1]
    total_points = user[1]*287 + user[2]*31 +user[3]*2 +quiz_points
    return user[0], total_points
 
print("User with ID:", find_total_points(user1)[0] , "has" , find_total_points(user1)[1] , "total points.")
print("User with ID:", find_total_points(user2)[0] , "has" , find_total_points(user2)[1] , "total points.")
print("User with ID:", find_total_points(user3)[0] , "has" , find_total_points(user3)[1] , "total points.")


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Revision as of 14:10, 10 April 2019

This a problem set for you to work through [1]

This is a problem set. Some of these are easy, others are far more difficult. The purpose of these problems sets are:

  1. to build your skill applying computational thinking to a problem
  2. to assess your knowledge and skills of different programming practices


What is this problem set trying to do[edit]

This is example problem set. In this example we are learning about lists and conditionals.

The Problem[edit]

Please consult the image of a leaderboard below

Leaderboard.png


You must design an algorithm which creates the total number of points. The algorithm accepts as input a comma delimited list:

USER ID, BADGES, CHALLENGES, VIDEOS, QUIZZES

For QUIZZES, the input is passed as a 2 dimensional list indicated the quiz number and the number of attempts. Please see below for two different examples of inputs:

1234, 3, 12, 13, [[1,1],[2,5],[3,1],[4,2]]

In the example above, user 1234 has 3 badges, 12 challenges, 13 videos and has the following quiz data:

  • for quiz 1, there was 1 attempt
  • for quiz 2, there was 5 attempts
  • for quiz 3, there was 1 attempt
  • for quiz 4 there were 2 attempts.

Your program should output the user ID and the number of points that user has earned. An example of out should look like:

1234, 340

How you will be assessed[edit]

Your solution will be graded using the following axis:


Scope

  • To what extent does your code implement the features required by our specification?
  • To what extent is there evidence of effort?

Correctness

  • To what extent did your code meet specifications?
  • To what extent did your code meet unit tests?
  • To what extent is your code free of bugs?

Design

  • To what extent is your code written well (i.e. clearly, efficiently, elegantly, and/or logically)?
  • To what extent is your code eliminating repetition?
  • To what extent is your code using functions appropriately?

Style

  • To what extent is your code readable?
  • To what extent is your code commented?
  • To what extent are your variables well named?
  • To what extent do you adhere to style guide?

References[edit]

A possible solution[edit]

Click the expand link to see one possible solution, but NOT before you have tried and failed!

#This awesome code was written by Filip from grade 11
#Hope you can learn something from this
#Date added 10.04.19

user1 = [123, 4, 13, 6, [[1,1],[2,5],[3,1],[4,2]]]
user2 = [842, 7, 20, 7, [[1,8],[2,4],[3,9],[4,20]]]
user3 = [945, 9, 12, 25, [[1,3],[2,1],[3,4],[4,34]]]

def find_total_points(user):
    for i in range (0, len(user[4])):
        quiz_points = 0
        quiz_points = quiz_points + user[4][i][-1]
    total_points = user[1]*287 + user[2]*31 +user[3]*2 +quiz_points
    return user[0], total_points

print("User with ID:", find_total_points(user1)[0] , "has" , find_total_points(user1)[1] , "total points.")
print("User with ID:", find_total_points(user2)[0] , "has" , find_total_points(user2)[1] , "total points.")
print("User with ID:", find_total_points(user3)[0] , "has" , find_total_points(user3)[1] , "total points.")